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Python

This file contains ambiguous Unicode characters!

This file contains ambiguous Unicode characters that may be confused with others in your current locale. If your use case is intentional and legitimate, you can safely ignore this warning. Use the Escape button to highlight these characters.

# -*- coding: utf-8 -*-
def money2chinese(money_number):
u"""
.转换数字为大写货币格式
@:param money_number: 金额(float, int, long, string 且小于15位)
@:return chinese_str: 大写的金额字符串
"""
format_word = [u"", u"", u"",
u"", u"", u"", u"",
u"", u"", u"", u"亿",
u"", u"", u"", u"",
u"", u"", u"", u""]
format_num = [u"", u"", u"", u"", u"", u"", u"", u"", u"", u""]
if isinstance(money_number, str):
# - 如果是字符串,先尝试转换成float或int.
try:
if '.' in money_number:
money_number = float(money_number)
else:
money_number = int(money_number)
except:
raise ValueError(u'不能识别的字符串:{0}'.format(money_number))
if isinstance(money_number, float):
real_numbers = []
money_len = len(str(money_number))
for i in range(money_len - 3, -3, -1):
if money_number >= 10 ** i or i < 1:
real_numbers.append(int(round(money_number / (10 ** i), 2) % 10))
elif isinstance(money_number, int):
real_numbers = [int(i) for i in str(money_number) + '00']
else:
raise ValueError(u'非法传参')
# 标记连续0次数以删除万字或适时插入零字
zflag = 0
start = len(real_numbers) - 3
chinese_words = []
# 使i对应实际位数负数为角分
for i in range(start, -3, -1):
if real_numbers[start - i] or len(chinese_words) == 0:
if zflag:
chinese_words.append(format_num[0])
zflag = 0
chinese_words.append(format_num[real_numbers[start - i]])
chinese_words.append(format_word[i + 2])
# 控制万/元
elif 0 == i or (0 == i % 4 and zflag < 3):
chinese_words.append(format_word[i + 2])
zflag = 0
else:
zflag += 1
if chinese_words[-1] not in (format_word[0], format_word[1]):
# 最后两位非"角,分"则补"整"
chinese_words.append("")
return ''.join(chinese_words)